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Overflow Error In Vb6.0

Code: Sub Breakeven() Dim i As Integer, j As Long, k As Byte, l As Long With ThisWorkbook For i = 0 To 9 j = 445000 + 10000 * i Hope this helps. What Am I doing wrong? Senior Software Engineer MCP, BSEE, CET VS 2012 Premium, VS 6.0 Enterprise SP6, VSTO, Office Ultimate 2010, Windows 7 Ultimate Star Wars Gangsta Rap SE Reputations & Rating Posts this contact form

So you need to assign a value within the Long range to fix the problem. 3. Results 1 to 8 of 8 Thread: overflow error #6 Tweet Thread Tools Show Printable Version Email this Page… Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch Learning resources Microsoft Virtual Academy Channel 9 MSDN Magazine Community Forums Blogs Codeplex Support Self support Programs BizSpark (for startups) Microsoft Imagine (for students) United States (English) Newsletter Privacy & cookies I have had similar problems in the past with VB6 or VBA not handling larger numbers. http://stackoverflow.com/questions/5895816/vb6-overflow-error-with-large-integers

Reference Trappable Errors Core Visual Basic Language Errors Core Visual Basic Language Errors 6 Overflow 6 Overflow 6 Overflow 3 Return without GoSub 5 Invalid procedure call or argument 6 Overflow Thus, when a is 1, the above statement generates character number 65, which is "A". RESOLVED THANK YOU FOR RECOGNIZING MY CONTRIBUTION AND RATING ME!

Results 1 to 4 of 4 Thread: [RESOLVED] VB6 OVERFLOW Error in code Tweet Thread Tools Show Printable Version Subscribe to this Thread… Display Linear Mode Switch to Hybrid Mode Switch Make sure your assignment fits the range for the property to which it is made. How do you say "you all" in Esperanto? Quite often, it's not worth "fixing" your code, if you can find another (preferably simpler) way to do what you want.

e.g if the value = 100, then range would become something like columns 1 to 100 rows 2:31 Or even better could not do something simpler like: For each column in Phil for the help. Debugging takes you to the following line in the code: RS = R / S Does anyone know what could be causing this. Still there's a Runtime Error-6 - Overflow and when i click the "DEBUG" it highlights: fact = fact * i but the good thing is i can now view the correct

Reply With Quote Mar 17th, 2007,05:46 AM #4 VBFnewcomer View Profile View Forum Posts Thread Starter Frenzied Member Join Date Aug 2006 Location India, Punjab, Bhatinda Posts 1,689 Re: VB6 OVERFLOW try: Dim fact As Long and see if it fixes the problem. Overflow error caused by Mod operator You face an overflow error if the operands of the Mod operator are larger than Long values, that means, when the operand outgrows the range To know about operators: Operators in VB6 Example: This code throws an overflow error.

Currency and Decimal are scaled integers. Perhaps double or currency will do... Dim intID as integer intID = x * 10000 Dim lngID AS Long lngID = x * CLng(10000) ' if 10000 ' whatever you want to be share|improve this answer edited In this context, you should learn about: Data type conversions Solution: Dim myResult As Long myResult=CLng(878*8787) Or, myResult=CLng(878) * 8787 Or, myResult=878*CLng(8787) Or, myResult=878 * 8787& 4.

The upper case letters are represented by the codes 65-90. weblink share|improve this answer edited Dec 31 '13 at 9:37 answered Dec 31 '13 at 9:32 Nagaraj S 7,19051637 add a comment| up vote 0 down vote I you have to put Working Environment Version: VB6 OS: ME/XP Office Applications: FAQs By RobDog888 * Great Excel tutorial by si_the_geek * VB6 Errors by Si * VB6 Controls: MSFlexgrid populate by si * RichText List Files by User-Defined Extensions Sending Data From MSFlexGrid To Excel in VB6 Send Data To Excel Using VB6 Folder Hider Masked Edit Control VB6 Create own User control - Basic

Find where that variable is declared. 4. Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Jun 26th, 2012,10:33 AM #2 Mindpsyche Board Regular Join Date Mar 2012 Location Hyderabad, India Posts 760 Re: VBA In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms navigate here Been quite busy.

Finally I want to recommend a few things. Anyway, in terms of fixing, could I not just utilise the following line of existing code in someway? Re-declare the variable to the appropriate data type or make sure something isn't wrong with your code that's causing it to put the wrong value into the variable.

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I read that dimming variables as long as opposed to integer can fix this problem but I tried this but I still get the same error. Advanced Search Forum Visual Basic Programming Visual Basic 6.0 Programming overflow error #6 If this is your first visit, be sure to check out the FAQ by clicking the link above. Not the answer you're looking for? You attempt to use a number in a calculation, and that number is coerced into an integer, but the result is larger than an integer.

Make sure your assignment fits the range for the property to which it is made. The problem is the code runs fine for the first six columns of data (i.e row 35 for columns A:F get populated with a correctly calculated statistic but code stops running The reason for this is that Integer stores values in the range of (-32,768) - (+ 32,767) and Longs store values in the range of (- 2,147,483,468) - (+ 2,147,483,468). http://sisei.net/overflow-error/overflow-error-in-frx.html Debugging takes you to the following line in the code "Set inputdata = Range(c)" It seems to be a different from the overflow error I was experiencing as this time it's

Register Help Remember Me? Yes No Additional feedback? 1500 characters remaining Submit Skip this Thank you! try: Dim fact As Long and see if it fixes the problem. This documentation is archived and is not being maintained.

Share Share this post on Digg Del.icio.us Technorati Twitter Reply With Quote Jun 26th, 2012,10:46 AM #5 Andrew Poulsom MrExcel MVPModerator Join Date Jul 2002 Posts 73,092 Re: VBA overflow error Re-implementation of assumed '' is valid only within an instance method '' cannot expose type '' outside the project through '' '' is ambiguous across the inherited interfaces '' Take a Long variable instead of Integer to overcome this error.